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Question: Prove function has even values

Saturday, 19 of January , 2008 at 2:26 pm

Question: Prove that the function n^2 -n has even values for all natural numbers (\mathbb{N} = \{0, 1, 2, 3 \ldots\}).

* Updated question for clarity.

Category: Algebra, Questions

2 Comments

Comment by Nikita Nikolaev

Made Friday, 25 of January , 2008 at 5:57 pm

Wait, how it be even if it isn’t even defined for  n<0?

Comment by eldila

Made Friday, 25 of January , 2008 at 6:13 pm

The question is to prove for all natural numbers which are defined as the following set: {1, 2, 3, …}.

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